5x^2+x=25

Solution for 5x^2+x=25 equation:

5x^2+x=25

We move all terms to the left:

5x^2+x-(25)=0

a = 5; b = 1; c = -25;
Δ = b2-4ac
Δ = 12-4·5·(-25)
Δ = 501
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{501}}{2*5}=\frac{-1-\sqrt{501}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{501}}{2*5}=\frac{-1+\sqrt{501}}{10}
$